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 Riemann surface equation RB ( f(z) ) = f( p(z) ) tommy1729 Ultimate Fellow Posts: 1,372 Threads: 336 Joined: Feb 2009 05/28/2014, 12:23 PM Let f(z) be an analytic function with a riemann surface that has branches. Let RB be shorthand for going from one specific Riemann Branch to another specific one. Then the equation that holds locally or globally : RB ( f(z) ) = f( p(z) ) with p(z) a degree 1 or 2 polynomial. fascinates me. For instance f(2z+1) is another branch of f(z). That is fascinating. But how to solve such a thing ? in particular RB ( f(z) ) = f(z + C) This relates to tetration and dynamics. Not sure if its in the books. Btw do not confuse with a simple invariant : p (f(z)) is another branch of f(z). which is different !! regards tommy1729 « Next Oldest | Next Newest »

 Messages In This Thread Riemann surface equation RB ( f(z) ) = f( p(z) ) - by tommy1729 - 05/28/2014, 12:23 PM RE: Riemann surface equation RB ( f(z) ) = f( p(z) ) - by tommy1729 - 05/29/2014, 07:22 PM

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