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[number theory] sieving with a_i mod p_i
#5
{0 mod 2, 0 mod 3 , 0 mod 5 , ... 0 mod prime 't' } does not define a certain a mod b.

Rather it sieves out possibilities of a mod b.

Its like 0 mod 2 , 0 mod 3 , 0 mod 5 gives :

1,7,11,13,17,19,23,29 mod 30.

A similar thing happens with a_i mod p_i.

But maybe that is what you actually meant (to say).

regards

tommy1729
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RE: [number theory] sieving with a_i mod p_i - by tommy1729 - 09/11/2014, 08:24 AM

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