10/03/2014, 09:41 PM

As for the exp^[a]( ln^[a](x) + ln^[a](y) ) case , I think I have something intresting ; numerical methods independant of a.

Need more research.

Looks promising.

Ok ok , I say a bit more :

solving for x when given a and b :

exp^[a]( 2 ln^[a] (x) ) = b

seems to have a method.

regards

tommy1729

Need more research.

Looks promising.

Ok ok , I say a bit more :

solving for x when given a and b :

exp^[a]( 2 ln^[a] (x) ) = b

seems to have a method.

regards

tommy1729