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Binary partition at oo ?
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(10/03/2014, 09:11 PM)tommy1729 Wrote: So it seems intuitive to conjecture that for both functions we have

f ( a + oo i ) = 0.

Actually, now that I've had more time to analyze things, I realize that the function grows at about the same rate in all directions. For example, in the negative direction, there are infinitely many zeroes. However, in between the zeroes, the function is oscillating, with each local minimum or local maximum being about 0.0016185 times the value of the function at the equivalent positive value.

For example, there are zeroes at approximately:
-1.8822219377154e30
-3.8040468193666e30

In between, there is a local minimum at about -2.6756571755e30. The value at the minimum, compared to the respective positive value:

f(-2.6756571755e30) ~= -1.672619088e1396
f(2.6756571755e30) ~= 9.295773339e1398

The ratio is about -0.0017993329

As we go further and further in the negative direction, this ratio comes down a little, bit seems to bottom out at +/- 0.0016185. This latter value can be calculated as follows:



This evaluates to approximately (0.004872868560797)/(3.01076739115959), which is approximately 0.001618480582427.

I'll show the way I derived those two summations in a later post, but it's basically a consequence of the formulas I showed in this link:
http://math.eretrandre.org/tetrationforu...53#pid7453

By the way, if we go off in the imaginary direction, we see a similar pattern, namely that the function grows at a near constant rate, relative to the respective values in the positive direction. Using a similar summation, we can even calculate that the constant in the imaginary direction is approximately 0.168663.
~ Jay Daniel Fox
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Messages In This Thread
Binary partition at oo ? - by tommy1729 - 10/03/2014, 09:11 PM
RE: Binary partition at oo ? - by jaydfox - 10/06/2014, 07:17 PM
RE: Binary partition at oo ? - by tommy1729 - 10/07/2014, 07:22 PM

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