10/10/2014, 11:51 PM

If an initial value x converges to a fixpoint at an angle y , we can give that value pair(x,y) a corresponding color depending on the angle y.

We can make a plot that would then be the analogue of a fractal , the coloring based on the values y corresponding to the x's.

---

That is the main idea ...

Some comments : the derivative at the fixpoints x_0 needs to be positive real.

SO :

Arg ( f ' (x_0) ) = 0

0 < Abs ( f ' (x_0) ) < 1

Also the case is simplest when f(z) only has 2 conjugate fixpoints.

***

Therefore I seek :

Taking - without loss of generality ? - the fixpoints equal to +/- i .

g(z) = real entire = ??

f(z) :=

exp(g(z)) (z^2+1) + z

Arg ( f ' (i) ) = 0

0 < Abs ( f ' (i) ) < 1

And also f(z) ~ exp(z) z^A for some small real A.

Many solutions g(z) must exist , but which is best ?

And how do the " new fractals " look like ?

---

Also can the angle be given by an integral ?

Contour integral ?

z_0 = initial value

z_n = f ( z_(n-1) )

lim n -> +oo

[z_n - z_(n-1)] / [ | z_n - z_(n-1) | ]

= contour integral ( z_0 ) ???

regards

tommy1729

We can make a plot that would then be the analogue of a fractal , the coloring based on the values y corresponding to the x's.

---

That is the main idea ...

Some comments : the derivative at the fixpoints x_0 needs to be positive real.

SO :

Arg ( f ' (x_0) ) = 0

0 < Abs ( f ' (x_0) ) < 1

Also the case is simplest when f(z) only has 2 conjugate fixpoints.

***

Therefore I seek :

Taking - without loss of generality ? - the fixpoints equal to +/- i .

g(z) = real entire = ??

f(z) :=

exp(g(z)) (z^2+1) + z

Arg ( f ' (i) ) = 0

0 < Abs ( f ' (i) ) < 1

And also f(z) ~ exp(z) z^A for some small real A.

Many solutions g(z) must exist , but which is best ?

And how do the " new fractals " look like ?

---

Also can the angle be given by an integral ?

Contour integral ?

z_0 = initial value

z_n = f ( z_(n-1) )

lim n -> +oo

[z_n - z_(n-1)] / [ | z_n - z_(n-1) | ]

= contour integral ( z_0 ) ???

regards

tommy1729