03/24/2015, 01:22 PM

Recently I posted a 3rd zeration and now Im considering a 4th.

It may be that the 3rd equals one of the first 2 and that the 4th is also equal to another.

Anyway here is the logic.

the base or unit satisfies approximately :

b[3]x = b^x => base change => x -> C * x = C[2]x

b[4]x = b^^x => base change => x -> C + x = C[1]x

b[5]x => base change => x -> C[0]x or C[0]x.

So from a pentation base change we get zeration.

Well maybe.

regards

tommy1729

It may be that the 3rd equals one of the first 2 and that the 4th is also equal to another.

Anyway here is the logic.

the base or unit satisfies approximately :

b[3]x = b^x => base change => x -> C * x = C[2]x

b[4]x = b^^x => base change => x -> C + x = C[1]x

b[5]x => base change => x -> C[0]x or C[0]x.

So from a pentation base change we get zeration.

Well maybe.

regards

tommy1729