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exp^[3/2](x) > sinh^[1/2](exp(x)) ?
#4
Bye contrast the half-iterates of x^2 and x^2 - 1/4 intersect infinitely often.

Regards

Tommy1729
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RE: exp^[3/2](x) > sinh^[1/2](exp(x)) ? - by tommy1729 - 04/23/2015, 04:54 PM

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