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Full Version: Inspired by the sqrt
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Two ideas are at play here

1) approximate f^[1/2](z) by a^[1/2](z) + b^[1/2](z) when f(z) = a(z) + b(z).

2) q(  q x ^ s )^s = q^{s+1} x^(s^2).

So when we try this to approximate 2sinh^[1/2](x), what do we get ?

G(x) = 0 + A1 x + A2 x^sqrt 2 + A3 x^sqrt 3 + ...

Need to think about that.

sent it mick From MSE too , so it might appear there.