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lemma 1

let f(z) be a real entire function with 2 conjugate fixpoints and no other fixpoints.

we define sf(z) as its superfunction and isf(z) as its inverse superfunction.

z and k are complex numbers.

if sf(isf(z) + k) is analytic with respect to z then it is also analytic with respect to k.

regards

tommy1729
(06/29/2011, 12:04 PM)tommy1729 Wrote: [ -> ]we define sf(z) as its superfunction and isf(z) as its inverse superfunction.

which superfunction?
(06/29/2011, 08:09 PM)bo198214 Wrote: [ -> ]
(06/29/2011, 12:04 PM)tommy1729 Wrote: [ -> ]we define sf(z) as its superfunction and isf(z) as its inverse superfunction.

which superfunction?

any superfunction.