03/12/2014, 06:43 PM

In this thread, there is mention of "Trappmann's Balanced Hyper-operator", and then there is a small section on it at the very end of the FAQ. I guess I finally have to learn about the Lambert W function...

Tetration Forum > Tetration and Related Topics > Mathematical and General Discussion > Generalized arithmetic operator

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03/12/2014, 06:43 PM

In this thread, there is mention of "Trappmann's Balanced Hyper-operator", and then there is a small section on it at the very end of the FAQ. I guess I finally have to learn about the Lambert W function...

03/21/2014, 10:31 PM

https://sites.google.com/site/tommy1729/...e-property

We use a uniqueness condition on sexp : for x,y >=0 : sexp(x+yi) is real entire.

We could change the base e to base 2 or change tetration to pentation to generalize things.

Imho that is the way to do hyperoperation and I believe that answers almost all questions. ( I read your paper ).

Imho there are 2 big questions remaining :

1) informally speaking : what lies between tetration and pentation ?

Once again I mean the " half-super functions " as has been discussed on this forum before ( mainly by myself and James Nixon ).

Let S mean "superfunction of ..." and S^[-1] "is the superfunction of ..."

We have S^[-1](f(x)) = f ( f^[-1](x)+1)

examples :

S(exp(x)) = sexp(x)

S^[-1](sexp(x)) = sexp(slog(x)+1) = exp(x)

Question : if we say S^[a+b](f(x)) = S^[a](S^[b](f(x)) = S^[b](S^[a](f(x))

Then what is S^[1/2](f(x)) ? Or what is S^[1/2](exp(x)) ?

(Question 2 is still under investigation and not formulated yet)

regards

tommy1729

We use a uniqueness condition on sexp : for x,y >=0 : sexp(x+yi) is real entire.

We could change the base e to base 2 or change tetration to pentation to generalize things.

Imho that is the way to do hyperoperation and I believe that answers almost all questions. ( I read your paper ).

Imho there are 2 big questions remaining :

1) informally speaking : what lies between tetration and pentation ?

Once again I mean the " half-super functions " as has been discussed on this forum before ( mainly by myself and James Nixon ).

Let S mean "superfunction of ..." and S^[-1] "is the superfunction of ..."

We have S^[-1](f(x)) = f ( f^[-1](x)+1)

examples :

S(exp(x)) = sexp(x)

S^[-1](sexp(x)) = sexp(slog(x)+1) = exp(x)

Question : if we say S^[a+b](f(x)) = S^[a](S^[b](f(x)) = S^[b](S^[a](f(x))

Then what is S^[1/2](f(x)) ? Or what is S^[1/2](exp(x)) ?

(Question 2 is still under investigation and not formulated yet)

regards

tommy1729

03/22/2014, 12:06 AM

Quote:what lies between tetration and pentation ?Do we know what lies between addition and multiplication, or multiplication and exponentiation? I would be happy to know those first. I assume they would be simpler to find, but I can also imagine that they would be equally difficult to find.

Quote:Question : if we say S^[a+b](f(x)) = S^[a](S^[b](f(x)) = S^[b](S^[a](f(x))I found an answer to part of your question. By that I mean I was able to find S^[1/2](exp(x)):

Then what is S^[1/2](f(x)) ? Or what is S^[1/2](exp(x)) ?

By definition:

So we are trying to find some function such that

If we define such that

then

, where W is the Lambert W function

There is your half-superfunction of exp(x).

03/22/2014, 12:13 AM

(03/22/2014, 12:06 AM)hixidom Wrote: [ -> ]Quote:what lies between tetration and pentation ?Do we know what lies between addition and multiplication, or multiplication and exponentiation? I would be happy to know those first. I assume they would be simpler to find, but I can also imagine that they would be equally difficult to find.

Quote:Question : if we say S^[a+b](f(x)) = S^[a](S^[b](f(x)) = S^[b](S^[a](f(x))I found an answer to part of your question. By that I mean I was able to find S^[1/2](exp(x)):

Then what is S^[1/2](f(x)) ? Or what is S^[1/2](exp(x)) ?

By definition:

So we are trying to find some function such that

If we define such that

then

, where W is the Lambert W function

There is your half-superfunction of exp(x).

Sorry for not using tex before but

By definition:

that is sufficient to see your answer is wrong ...

Sorry.

regards

tommy1729

03/22/2014, 12:42 AM

Ah. I see.

By half-superfunction, I thought you meant the superfunction of exp(x), S(x,n), evaluated at n=1/2.

But I guess you're talking about the superfunction of S(x,n), , evaluated at m=1/2.

Since S is a function of 2 variables, I guess I have to ask...

Is , , or ?

By half-superfunction, I thought you meant the superfunction of exp(x), S(x,n), evaluated at n=1/2.

But I guess you're talking about the superfunction of S(x,n), , evaluated at m=1/2.

Since S is a function of 2 variables, I guess I have to ask...

Is , , or ?

03/22/2014, 09:38 AM

Superfunction is a multivalued function defined over a set of functions not over a set of numbers:

means that takes a function and gives a function calles superfunction of

such that satisfies

1)

since there are infinite solution for (infinite superfunctions) that means that is multivalued and then is not a function at all and we have to put some restrictions:

using Trapmann-Kouznetsov terminology used in their paper "5+ methods..." we call the -based superfunction of the function that satifies two requirements

1)

2)

and we have

In this way we obtain uniqueness over the naturals: in fact superfunction is equivalent to the "definition by recursion" that is unique .

But is not over the reals... there we need more requirments.

Obviously this is still not enough to achieve the uniqueness of (iteration of ) that would mean having to be a function over a set of functions (not multivalued).

By the way I guess that Trapmann and Kouznetsov tried to find such additionals requirments but my math level is not enough to understand it.

Anyways we have that is a function and is the half superfunction.

example :

let define and we have

(multiplication is the 0-based superfunction of addition)

so we search for a such that

and that if we should have (maybe...)

and

I apologize if I did some mistakes.

means that takes a function and gives a function calles superfunction of

such that satisfies

1)

since there are infinite solution for (infinite superfunctions) that means that is multivalued and then is not a function at all and we have to put some restrictions:

using Trapmann-Kouznetsov terminology used in their paper "5+ methods..." we call the -based superfunction of the function that satifies two requirements

1)

2)

and we have

In this way we obtain uniqueness over the naturals: in fact superfunction is equivalent to the "definition by recursion" that is unique .

But is not over the reals... there we need more requirments.

Obviously this is still not enough to achieve the uniqueness of (iteration of ) that would mean having to be a function over a set of functions (not multivalued).

By the way I guess that Trapmann and Kouznetsov tried to find such additionals requirments but my math level is not enough to understand it.

Anyways we have that is a function and is the half superfunction.

example :

let define and we have

(multiplication is the 0-based superfunction of addition)

so we search for a such that

and that if we should have (maybe...)

and

I apologize if I did some mistakes.

06/11/2014, 05:10 PM

So here is a link to the updated document. I've added a little bit on non-integer iteration of the [x] operator as well as [x] for non-integer x. I used the results to write matlab code that plots over ranges of a, n, and x values. The plots are also in the document. There are still some limitations, but the expansion method (See http://arxiv.org/pdf/hep-th/9707206v2.pdf, pg.31) seems to work very well for x<3 and a,n<2. blows up for larger values of a and/or n, as expected, and the expansion produces poor results for x>3, since I currently only know inverse operations for [1], [2], and [3], and so my expansions for non-integer x are limited to 4 terms.

Plot over a:

[attachment=1067]

Plot over n:

[attachment=1066]

Plot over x:

[attachment=1068]

Plot over a:

[attachment=1067]

Plot over n:

[attachment=1066]

Plot over x:

[attachment=1068]

Tetration Forum > Tetration and Related Topics > Mathematical and General Discussion > Generalized arithmetic operator

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