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Full Version: Conjecture on semi-exp base change [2015]
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Let x,y > 0.
Let B>b>2.

Expb is exp base b and expB is exp base B.
Analogue for ln.
Conjecture :

A(x,y) = expB^[1/2](lnB^[1/2](x) + lnB^[1/2](y))
B(x,y) = expb^[1/2](lnb^[1/2](x) + lnb^[1/2](y))
C(x,y) = (2+x^2+y^2)^(B-b)

A(x,y)/( B(x,y) ln(2+C(x,y)) ) < 2

Regards

Tommy1729