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Maybe the solution at z=0 to f(f(z))=-z+z^2
Who Posted?
Who Posted?
| Total Posts: 10 | |
| User | # Posts |
| Leo.W | 5 |
| tommy1729 | 4 |
| JmsNxn | 1 |
Who Posted?
| Total Posts: 10 | |
| User | # Posts |
| Leo.W | 5 |
| tommy1729 | 4 |
| JmsNxn | 1 |