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Tommy-Gottfried divisions. - Printable Version

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Tommy-Gottfried divisions. - tommy1729 - 10/09/2015

If we divide exp by 1 + x we get another Taylor that starts with 1.

Exp(x)/(1+x) = 1 + a x^2 + ...

We could repeat by dividing by (1 + a x^2).

This results in Gottfried's pxp(x) and " dream of a sequence ".

Notice it gives a product expansion that suggests zero's for exp.
" fake zero's " sort a speak.

Im considering analogues.

Start with exp(x) / (1 + x + x^2/2) maybe ?

I think I recall Some impossibility or critisism about such variants. But I forgot what that was.

Regards

Tommy1729