Tetration Forum
Iterations of ln(mod(ln(x^(1/x))) and number with property Left a[4]n=exp (-(a^(n+1)) - Printable Version

+- Tetration Forum (https://math.eretrandre.org/tetrationforum)
+-- Forum: Tetration and Related Topics (https://math.eretrandre.org/tetrationforum/forumdisplay.php?fid=1)
+--- Forum: Mathematical and General Discussion (https://math.eretrandre.org/tetrationforum/forumdisplay.php?fid=3)
+--- Thread: Iterations of ln(mod(ln(x^(1/x))) and number with property Left a[4]n=exp (-(a^(n+1)) (/showthread.php?tid=139)



Iterations of ln(mod(ln(x^(1/x))) and number with property Left a[4]n=exp (-(a^(n+1)) - Ivars - 03/30/2008

I have been playing with iterations of



And of course I tried and

is not very interesting, it converges to 2 values depending on integer iteration number. Here are picture of 200 iterations:
[attachment=283]


is more interesting. This iteration converges to 4 values for each x, cyclicaly,and their dependance on n is shifting depending the region x is in the interval ]0:1[. The convergence values are :



Here is what happens:

[attachment=284]


[attachment=287]


When resolution is increased (step decreased) more and more shifts in phase happen in the region which seems to converge to approximately 0,6529204....

[attachment=285]

[attachment=286]


This number has properties:







So its 2nd selfroot is , while its reciprocal 1,531580266.. is 3rd superroot of e.

It has also following properties, at least approximately numerically, so it might be wrong, but interesting:

if we denote it , than:





So:





........





..........

if this is so, what happens if instead of integer n we take x, so that:

maybe:




I hope I used [4Left] correctly. So:

and



If accuracy is not enough, so it is numerically only 3-4 digits, perhaps going for n-th superroot of e would improve situation?

Probably this is old knowledge.

Ivars