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 Tommy-Gottfried divisions. tommy1729 Ultimate Fellow Posts: 1,438 Threads: 349 Joined: Feb 2009 10/09/2015, 07:39 AM If we divide exp by 1 + x we get another Taylor that starts with 1. Exp(x)/(1+x) = 1 + a x^2 + ... We could repeat by dividing by (1 + a x^2). This results in Gottfried's pxp(x) and " dream of a sequence ". Notice it gives a product expansion that suggests zero's for exp. " fake zero's " sort a speak. Im considering analogues. Start with exp(x) / (1 + x + x^2/2) maybe ? I think I recall Some impossibility or critisism about such variants. But I forgot what that was. Regards Tommy1729 « Next Oldest | Next Newest »

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