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 Tommy's Gamma trick ? tommy1729 Ultimate Fellow Posts: 1,372 Threads: 336 Joined: Feb 2009 10/16/2015, 12:28 PM So we divide the interval (1,2) into K pieces. Then we define m variabels est(m/k) = sexp(m/K + 1) for 1 =< m =< k. Also the derivative is estimated (est(m/k) - est((m-1)/k))/k. And est ' (0) = est ' (1/k) = 1 , est ' (1) = e. More later. Regards Tommy1729 « Next Oldest | Next Newest »

 Messages In This Thread Tommy's Gamma trick ? - by tommy1729 - 10/14/2015, 09:37 PM RE: Tommy's Gamma trick ? - by tommy1729 - 10/16/2015, 12:28 PM RE: Tommy's Gamma trick ? - by tommy1729 - 10/17/2015, 12:22 AM RE: Tommy's Gamma trick ? - by tommy1729 - 10/22/2015, 12:34 PM RE: Tommy's Gamma trick ? - by tommy1729 - 11/02/2015, 01:43 AM RE: Tommy's Gamma trick ? - by tommy1729 - 11/04/2015, 12:06 AM RE: Tommy's Gamma trick ? - by tommy1729 - 11/04/2015, 01:26 PM RE: Tommy's Gamma trick ? - by tommy1729 - 11/07/2015, 01:02 PM

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