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Tommy's Gamma trick ?
#2
So we divide the interval (1,2) into K pieces.
Then we define m variabels est(m/k) = sexp(m/K + 1) for 1 =< m =< k.

Also the derivative is estimated (est(m/k) - est((m-1)/k))/k.

And est ' (0) = est ' (1/k) = 1 , est ' (1) = e.

More later.

Regards

Tommy1729
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Messages In This Thread
Tommy's Gamma trick ? - by tommy1729 - 10/14/2015, 09:37 PM
RE: Tommy's Gamma trick ? - by tommy1729 - 10/16/2015, 12:28 PM
RE: Tommy's Gamma trick ? - by tommy1729 - 10/17/2015, 12:22 AM
RE: Tommy's Gamma trick ? - by tommy1729 - 10/22/2015, 12:34 PM
RE: Tommy's Gamma trick ? - by tommy1729 - 11/02/2015, 01:43 AM
RE: Tommy's Gamma trick ? - by tommy1729 - 11/04/2015, 12:06 AM
RE: Tommy's Gamma trick ? - by tommy1729 - 11/04/2015, 01:26 PM
RE: Tommy's Gamma trick ? - by tommy1729 - 11/07/2015, 01:02 PM

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