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 The balanced hyperop sequence bo198214 Administrator Posts: 1,389 Threads: 90 Joined: Aug 2007 04/18/2008, 05:58 PM andydude Wrote:$x[n+1]2^t = f_n^t(x)$ as you mentioned, so $x[1]1 = f_0^0(x) = x$ because it is the identity function, but $x[1]1 = x + 1$ by definition of addition! therefore, $f_0(x) = x[0]x$ cannot exist. This is a nice proof, thanks. Quote:... prove it differently, as I did in an email to you awhile back. An e-mail to me? I dont remember, did I reply? « Next Oldest | Next Newest »

 Messages In This Thread The balanced hyperop sequence - by bo198214 - 04/14/2008, 08:44 AM RE: The balanced hyperop sequence - by andydude - 04/18/2008, 05:23 PM RE: The balanced hyperop sequence - by bo198214 - 04/18/2008, 05:58 PM RE: The balanced hyperop sequence - by bo198214 - 04/18/2008, 06:20 PM RE: The balanced hyperop sequence - by andydude - 04/20/2008, 02:28 AM RE: The balanced hyperop sequence - by bo198214 - 04/26/2008, 07:20 PM RE: The balanced hyperop sequence - by bo198214 - 11/30/2009, 11:37 PM

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