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 Kneser's Super Logarithm mike3 Long Time Fellow Posts: 368 Threads: 44 Joined: Sep 2009 01/26/2010, 06:24 AM (01/25/2010, 07:42 AM)sheldonison Wrote: (01/25/2010, 06:35 AM)mike3 Wrote: What do you mean by $\ln_f$?Typo, that should've been $\log_f$ f=fixed point of "e", 0.318131505+1.337235701i, $\ln(f)=f$ $\log_f(z)=\ln(z)/\ln(f))=(1/f)*\ln(z)$ For clairty, I'm also changing this in the original reply I made. - Sheldon Ah. So how would you use the given equation to calculate $\theta(z)$? « Next Oldest | Next Newest »

 Messages In This Thread Kneser's Super Logarithm - by bo198214 - 11/19/2008, 02:20 PM RE: Kneser's Super Logarithm - by bo198214 - 11/19/2008, 03:25 PM RE: Kneser's Super Logarithm - by sheldonison - 01/23/2010, 01:01 PM RE: Kneser's Super Logarithm - by mike3 - 01/25/2010, 06:35 AM RE: Kneser's Super Logarithm - by sheldonison - 01/25/2010, 07:42 AM RE: Kneser's Super Logarithm - by mike3 - 01/26/2010, 06:24 AM RE: Kneser's Super Logarithm - by sheldonison - 01/26/2010, 01:22 PM RE: Kneser's Super Logarithm - by mike3 - 01/27/2010, 06:28 PM RE: Kneser's Super Logarithm - by sheldonison - 01/27/2010, 08:30 PM RE: Kneser's Super Logarithm - by mike3 - 01/28/2010, 08:52 PM RE: Kneser's Super Logarithm - by sheldonison - 01/28/2010, 10:08 PM RE: Kneser's Super Logarithm - by mike3 - 01/29/2010, 06:43 AM RE: Kneser's Super Logarithm - by bo198214 - 01/26/2010, 11:19 PM RE: Kneser's Super Logarithm - by sheldonison - 01/27/2010, 07:51 PM RE: Kneser's Super Logarithm - by bo198214 - 11/22/2008, 06:11 PM RE: Kneser's Super Logarithm - by bo198214 - 11/23/2008, 01:00 PM

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