Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
using the sum , hoping for convergence
#1
without going into details , the idea is simple.

ignoring some details we consider :

we have a continuum sum operator.

tet'(x) = tet'(0)* continuum product till tet(x).

we can use the continuum sum to compute the continuum product.

once we have tet'(x) , we can find tet(x) by integration.

the problem with the above is that its an equation with selfreference.

the proposed solution is to do the same but with iteration.

consider any coo solution to tet(x).

thats our starting function tet_0(x).

tet_1 ' (x) = tet_0 ' (0) * continuum product till tet_0 (x).

tet_1 (x) = integral tet_1 ' (x).

we continue :

tet_2 ' (x) = tet_1 ' (0) * continuum product till tet_1 (x).

tet_2 (x) = integral tet_2 ' (x).


etc

till we get our converging limit.


basicly ...

tommy1729
Reply


Messages In This Thread
using the sum , hoping for convergence - by tommy1729 - 08/25/2010, 06:07 PM

Possibly Related Threads...
Thread Author Replies Views Last Post
  Integer tetration and convergence speed rules marcokrt 5 7,080 12/21/2011, 06:21 PM
Last Post: marcokrt
  What is the convergence radius of this power series? JmsNxn 9 15,279 07/04/2011, 09:08 PM
Last Post: JmsNxn
  Nowhere analytic superexponential convergence sheldonison 14 17,342 02/10/2011, 07:22 AM
Last Post: sheldonison



Users browsing this thread: 1 Guest(s)