06/07/2011, 07:47 AM
(08/28/2010, 11:23 PM)tommy1729 Wrote: log(tet'(z+r)) + A = log(tet'(z)) + B?
hence bending points in
sexp(slog(z) + r) correspond to bending points in sexp(z).
I dont see how that follows, nor does it seem to be right.
For example the fractional iterates of c^x, c>eta have no bending points imho,
while the curvature of sexp in (-2,0) seems to be negative for me, while for greater x it appears to be positive. So there must be a bending point somewhere.