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blunder ?? f(x) = f(x^2)
#2
the post contains some mistakes ...

will correct later.

meanwhile for abs(z) < 1 and <> 0 sum (n, -oo , oo) x^2^n

seems a solution.
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blunder ?? f(x) = f(x^2) - by tommy1729 - 08/29/2010, 09:13 PM
RE: blunder ?? f(x) = f(x^2) - by tommy1729 - 08/30/2010, 11:40 PM



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