11/15/2007, 09:44 AM

hej jaydfox,

Thanks. I know how annoying such elementary things can be.

But I would end up with ln(sqrt(2)) +- pi I +- 2pi I k?

Ivars

Thanks. I know how annoying such elementary things can be.

jaydfox Wrote: or ln(sqrt(2)) +- (2k+1)pi I, or if you really need to factor out k and put it at the end of the expression, then ln(sqrt(2)) + pi I +- 2 pi I k

But I would end up with ln(sqrt(2)) +- pi I +- 2pi I k?

Ivars