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superfunctions of eta converge towards each other
#13
perhaps not so relevant but the following idea inspires me :

sexp(f(z)) = cheta(f(z))

f(z) satisfies f(z) = f(z) + theta(f(z)) + k

hence theta(f(z)) = -k

but theta is not a constant function , thus there is no f(z) apart from id(z).

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RE: superfunctions of eta converge towards each other - by tommy1729 - 06/06/2011, 10:42 PM

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