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 [AIS] (alternating) Iteration series: Half-iterate using the AIS? Gottfried Ultimate Fellow Posts: 763 Threads: 118 Joined: Aug 2007 12/06/2012, 12:10 AM (This post was last modified: 03/31/2015, 11:41 AM by Gottfried.) I'm still looking at the whereabouts of series of iterates, like $s(x)=x-b^x+b^{b^x} -b^{b^{b^x} } + ... - ...$ and consider the potential of such series for the definition of half-iterates, independently of the selection of fixpoints and the fractional "regular tetration" and similar goodies. The best approach so far to make this compatible with criteria like summability (we cannot have convergence in the following definitions) seems to be the following ansatz. We take a base, say b=1.3, and use the decremented exponentiation $f:x \to b^x-1$, such that we have two real fixpoints. Then we can select any abscissa x_0 between that fixpoints and iterate infinitely to positive heights and to negative heights as well, getting $x_1,x_2,...$ and $x_{-1},x_{-2},...$. The alternating series of all that iterates is then Cesaro- or Euler-summable to some finite value $S(x)$. Obviously this is periodic with $S(f^{[2+h]}(x))=S(f^{[h]}(x))$ and also sinusoidal. With that base b=1.3 I find for instance at $x_0 \sim 0.427734366938$ that $S(x_0)=0$. After this it is surely natural to assume, that beginning at the first iterate we have also that $S(x_1)=0$, but it seems also natural to assume, that then the maxima or the minima of the sinusoidal curve of all $S(x_0)...S(x_1)$ are at the half-iterates between them. Well, this is the crucial assumtion for my discussion here, which must prove to be sensical. Now if I let Pari/GP search for the first extremum in that curve I get the abcissa $x_{\min\text{(serial)}} \sim 0.2273401 546757$ . If I compute the halfiterate using the regular tetration via the squareroot of the formal powerseries/the Schröder-function mechanism, I get $x_{0.5 \small \text{(regular)}} \sim 0.2273401 704241$ which is very close, but only to some leading digits. The values of the infinite series beginning at these values differ only by 1e-16 and smaller, so maybe the non-match is an artifact (which I do not believe). Do you have any opinion about this or even any idea how to proceed to make it an interesing item (say we find some method where $x_{0.5 \small \text{(yourmethod}) } \sim x_{\min( \small \text{serial})}$) or simply - that it would be better to put this all aside for a good reason? (I can provide the Pari/GP-routines if this would be convenient) Gottfried [update] : I adapted the title to improve the organization of the thrads-list Gottfried Helms, Kassel « Next Oldest | Next Newest »

 Messages In This Thread [AIS] (alternating) Iteration series: Half-iterate using the AIS? - by Gottfried - 12/06/2012, 12:10 AM RE: Half-iterate using the infinite iteration-series? - by tommy1729 - 12/08/2012, 06:27 PM RE: Half-iterate using the infinite iteration-series? - by Gottfried - 12/09/2012, 03:13 PM RE: Half-iterate using the infinite iteration-series? - by Gottfried - 12/10/2012, 02:23 AM RE: Half-iterate using the infinite iteration-series? - by mike3 - 12/10/2012, 03:33 AM RE: Half-iterate using the infinite iteration-series? - by Gottfried - 12/10/2012, 10:38 AM RE: Half-iterate using the infinite iteration-series? - by mike3 - 12/10/2012, 11:26 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by sheldonison - 12/11/2012, 12:44 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/11/2012, 01:16 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by sheldonison - 12/13/2012, 02:49 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by sheldonison - 12/15/2012, 04:47 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/15/2012, 06:49 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by sheldonison - 12/15/2012, 01:43 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/15/2012, 11:27 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/16/2012, 12:05 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by sheldonison - 12/17/2012, 10:19 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/18/2012, 11:17 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by sheldonison - 12/22/2012, 04:12 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/23/2012, 09:01 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by sheldonison - 12/23/2012, 03:51 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Nasser - 12/14/2012, 05:06 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/14/2012, 07:16 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/15/2012, 06:37 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by andydude - 12/18/2012, 06:05 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by tommy1729 - 12/15/2012, 10:06 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/23/2012, 04:43 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 12/23/2012, 05:59 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 01/02/2013, 03:28 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 01/02/2013, 04:05 PM RE: Iteration series: Half-iterate using the infinite iteration-series? - by Gottfried - 01/03/2013, 07:07 AM RE: Iteration series: Half-iterate using the infinite iteration-series? - by sheldonison - 01/03/2013, 09:58 PM RE: [AIS] (alternating) Iteration series: Half-iterate using the AIS? - by Gottfried - 03/26/2015, 01:01 PM RE: [AIS] (alternating) Iteration series: Half-iterate using the AIS? - by tommy1729 - 03/27/2015, 11:28 PM

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