08/12/2013, 12:10 AM
Notice how the superfunction of a x^b involves the generalizations.
e.g. f ' (x) = f^[2,5](x)
regards
tommy1729
e.g. f ' (x) = f^[2,5](x)
regards
tommy1729
Solutions to f ' (x) = f(f(x)) ?
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Solutions to f ' (x) = f(f(x)) ? - by tommy1729 - 08/11/2013, 11:49 PM
RE: Solutions to f ' (x) = f(f(x)) ? - by tommy1729 - 08/12/2013, 12:10 AM
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