Anyway, I made a graph cause it looks nice.

The part from x= 0.9-1.1 (base) is actually going to -infinity left of base=1, + infinity right of base=1 , but i did not calculate the points since then the rest of graph becomes invisible.

If the idea is right, there one can choose pairs (base<1) or triples (base>1) of real bases and heights giving 1 as a result of b[4]height.

base[4]height=1

I changed the name of the graph as it was wrong- it is finite real tetrations h of base b=a^(1/a) such that b[4]h=1 .

Ivars

The part from x= 0.9-1.1 (base) is actually going to -infinity left of base=1, + infinity right of base=1 , but i did not calculate the points since then the rest of graph becomes invisible.

If the idea is right, there one can choose pairs (base<1) or triples (base>1) of real bases and heights giving 1 as a result of b[4]height.

base[4]height=1

I changed the name of the graph as it was wrong- it is finite real tetrations h of base b=a^(1/a) such that b[4]h=1 .

Ivars