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 Super-logarithm on the imaginary line andydude Long Time Fellow Posts: 509 Threads: 44 Joined: Aug 2007 11/15/2007, 05:52 PM Right, since the real part of all points in the "backbone" of the slog are less than the logarithm of the radius of convergence, the exponential of them is within the radius of convergence (of the series expansion about z=0). Andrew Robbins « Next Oldest | Next Newest »

 Messages In This Thread Super-logarithm on the imaginary line - by andydude - 11/15/2007, 08:40 AM RE: Super-logarithm on the imaginary line - by jaydfox - 11/15/2007, 09:08 AM RE: Super-logarithm on the imaginary line - by jaydfox - 11/15/2007, 09:25 AM RE: Super-logarithm on the imaginary line - by andydude - 11/15/2007, 05:52 PM

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