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 Principal Branch of the Super-logarithm andydude Long Time Fellow Posts: 509 Threads: 44 Joined: Aug 2007 01/10/2008, 08:19 AM jaydfox Wrote:(from this thread) Exponentiate any point on the left boundary, and we'll get a point on the right boundary. Conversely, take the logarithm of any point on the right boundary, and we'll end up with a point on the left boundary. And of course, the fixed points complete the enclosure of this region. Using this knowledge, that "big red line" is the logarithm of the straight line between the two primary fixed points. And if we consider the last one Branch System D, then we can still use Branch System A as the standard branch cuts. Or in other words, if $\text{slog}(z)$ is Branch System A, then $\text{slog}(e^z) - 1$ would be Branch System D! Andrew Robbins « Next Oldest | Next Newest »

 Messages In This Thread Principal Branch of the Super-logarithm - by andydude - 11/17/2007, 10:58 AM RE: Principal Branch of the Super-logarithm - by jaydfox - 11/18/2007, 05:36 AM RE: Principal Branch of the Super-logarithm - by andydude - 11/21/2007, 10:00 PM RE: Principal Branch of the Super-logarithm - by andydude - 12/10/2007, 04:46 AM RE: Principal Branch of the Super-logarithm - by jaydfox - 12/11/2007, 03:00 AM RE: Principal Branch of the Super-logarithm - by andydude - 12/11/2007, 07:31 AM RE: Principal Branch of the Super-logarithm - by andydude - 01/10/2008, 08:19 AM RE: Principal Branch of the Super-logarithm - by tommy1729 - 06/20/2011, 09:32 PM

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