03/29/2015, 05:47 PM
In case it was not clear , I think the zeration will be the one that satisfies 2[0]2[0] ... = x + 2 or this one a[0]b = ln(exp(a)+exp(b) ).
The ackermann recursion makes no sense in this context for pentation.
Numerical experiments seem hard at first because of the speed of pentation.
And I have 0 theory.
But maybe others have ideas.
regards
tommy1729
The ackermann recursion makes no sense in this context for pentation.
Numerical experiments seem hard at first because of the speed of pentation.
And I have 0 theory.
But maybe others have ideas.
regards
tommy1729