The general equation is ^{^{y}a}=(^{y+1}a)^{^{x-1}a}})
Because^{^{y}a}\,=\,(a^{^{x-1}a})^{^{y}a}}\,=\,a^{^{x-1}a.\,^{y}a}\,=\,(a^{^{y}a})^{^{x-1}a}\,=\,(^{y+1}a)^{^{x-1}a })
It is somewhat trivial.
Because
It is somewhat trivial.
I have the result, but I do not yet know how to get it.
Should tetration be a multivalued function?
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