11/27/2017, 01:44 PM

Hi, everyone!

I have been working on the so-called iterated analysis. And I have found an interesting formula in that I am not so sure, so I share it with you to discuss it.

So, what if I say:

lim h->infinity super 1/h-th root of ( (f^^N)-th root of f^^N ) = lim h->infinity (super 1/h-th root of ((f)-th root of f))^^N

which is equivalent to

super 0th root of ( (f^^N)-th root of f^^N ) = (super 0th root of ((f)-th root of f))^^N

1st question: How can we calculate the super 0th root of a number or a function?

Any idea?

I have been working on the so-called iterated analysis. And I have found an interesting formula in that I am not so sure, so I share it with you to discuss it.

So, what if I say:

lim h->infinity super 1/h-th root of ( (f^^N)-th root of f^^N ) = lim h->infinity (super 1/h-th root of ((f)-th root of f))^^N

which is equivalent to

super 0th root of ( (f^^N)-th root of f^^N ) = (super 0th root of ((f)-th root of f))^^N

1st question: How can we calculate the super 0th root of a number or a function?

Any idea?

Xorter Unizo