03/21/2015, 12:35 AM
(03/20/2015, 10:41 PM)marraco Wrote: He will have a hard time, because he does not know what we call integer numbers. He only knows powers of n, so he will try to assign
a=1.a
a+a=n.a
a+a+a=n².a
a+a+a+a=n³.a
If n=2 then [only we know that] the correct addition would be
a=1.a
a+a=2.a
(a+a) + (a+a)=n².a
((a+a) + (a+a)) + ((a+a) + (a+a)) =n³.a
I terms of zeration, it should be
f=f+0
f°f=f+1
(f°f) ° (f°f)=f+2
((f°f) ° (f°f)) ° ((f°f) ° (f°f)) =f+3
(f+n)°(f+n)=f+(n+1)
and the natural choice for f, should be the neutral element of addition, so
0 = 0
0°0 = 1
(0°0) ° (0°0) = 1°1 = 2
((0°0) ° (0°0)) ° ((0°0) ° (0°0)) = 2°2 =3
(0+n)°(0+n) = n°n = (n+1)