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 Is it Tommy somewhere grassshopper Junior Fellow Posts: 3 Threads: 1 Joined: Apr 2021 08/16/2021, 10:56 PM Hi, Tetration Community is it active a user called Tommy, if it is the case then : w = (-3 # +5 # *11 # @23) reciprocalOf(w) = -(5068/228144) # +(5572/228144) # *(364/228144) # @16156/228144) w·reciprocalOf(w) = -1 # +1 @ *1 # @2 = @1 path : w = -a # +b # *c # @d where # is addition symbol in p4 example with -3 # +5 # *11 # @23 1/w = 1/(-a # +b # *c # @d) w~= -'a # +b # *'c # @d where s' m <-> aditiveInverseOf( sm ) 1/w = (1/w)(w~/w~) = w~/(ww~) w~/(ww~) = (-'a # +b # *'c # @d ) / ( ( -a # +b # *c # @d) (-'a # +b # *'c # @d) ) w~/(ww~) = (-'3 # +5 # *'11 # @23) / ( ( -3 # +5 # *11 # @23)(-'3 # +5 # *'11 # @23) ) w~/(ww~) = (-'a # +b # *'c # @d ) / (+'a^2 # @b^2 # +'c^2 # @d^2 # @'2ac # +2bd ) w~/(ww~) = (-'3 # +5 # *'11 # @23) / ( +'9 # @25 # +'121 # @529 # @'66 # +230 ) Note that is enough with express the statement just with the signs @, + ,@' and +' and is not necessary convert if remain symbol @' and +'... w~/(ww~) = (-'3 # +5 # *'11 # @23) / ( @480 # +100 ) Now, we complete to make difference of squares in the denominator , but one must be careful to complete it towards the greatest number, not the smallest as (x # y)(x # y') if x>y, or as (x # y)(x' # y) if x

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