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 Series for x-tetra-x andydude Long Time Fellow Posts: 509 Threads: 44 Joined: Aug 2007 04/27/2009, 10:14 PM (This post was last modified: 04/28/2009, 12:12 AM by andydude.) I just found a nice "power series" for ${}^{x}x$. It's based on regular iteration, and I took the regular iteration power series for $\exp_x^y(z)$ and evaluated it at (z=1), then substituted (y=x) to obtain a power series for ${}^{x}x$. At this point, I noticed there were lots of logarithms, or in other words, it seemed to be of the form $\sum_{j\ge 0} \sum_{k\ge 0} A_{jk} x^j \ln(x)^k$ which is nice, but not very interesting. It was when I noticed that the power series expansion of $x^x$ about 0 also produces this kind of series that I thought the two could be combined to make a new kind of series. So I tried doing some linear algebra change-of-basis stuff but I forgot how, so I used "undetermined coefficients" instead. I want to discuss this more, but it will have to wait until this weekend. Here is the power series. $ \begin{tabular}{rl} (x + 1) \uparrow\uparrow (x + 1) & = 1 \\ & + x \\ & + x^2 (1 - x^x) \\ & + \frac{x^3}{2}(3 - 3 x^x) \\ & + \frac{x^4}{3!}(14 - 17 x^x) \\ & + \frac{x^5}{4!}(96 - 119 x^x - 12 x^{2x}) \\ & + \frac{x^6}{5!2}(1698 - 2013 x^x - 420 x^{2x}) \\ & + \frac{x^7}{6!4}(37448 - 41199 x^x - 15480 x^{2x}) \\ & + \cdots \end{tabular}$ [update]Fixed some coefficient signs[/update] Andrew Robbins « Next Oldest | Next Newest »

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