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10^^(-3) = ?
#1
10^^(-1) = 0
10^^(-2) = -oo

you get to calculate:
10^^(-3) = ?

please! but I know! Tongue
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#2
(09/08/2009, 03:30 PM)nuninho1980 Wrote: 10^^(-1) = 0
10^^(-2) = -oo

you get to calculate:
10^^(-3) = ?

please! but I know! Tongue

Also a singularity? Like at every integer < -1.
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#3
(09/08/2009, 03:45 PM)bo198214 Wrote: Also a singularity? Like at every integer < -1.
lool
is the result real number or complex? Tongue
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#4
(09/08/2009, 04:06 PM)nuninho1980 Wrote:
(09/08/2009, 03:45 PM)bo198214 Wrote: Also a singularity? Like at every integer < -1.
lool
is the result real number or complex? Tongue

Neither, its a singularity.
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#5
(09/08/2009, 04:51 PM)bo198214 Wrote: Neither, its a singularity.
10^^-3 = oo + .......... ~= oo + .........i
which is these 1st exact number and 2nd aprox. number?
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#6
(09/08/2009, 05:10 PM)nuninho1980 Wrote:
(09/08/2009, 04:51 PM)bo198214 Wrote: Neither, its a singularity.
10^^-3 = oo + .......... ~= oo + .........i
which is these 1st exact number and 2nd aprox. number?

Doesnt that depend on the path on which you approach the singularity?
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#7
(09/09/2009, 12:04 PM)bo198214 Wrote: Doesnt that depend on the path on which you approach the singularity?
you failed. lol
oo + log_10 (-1) ~= oo + 1.364376354i Smile
do you forget!?

do you want more to calculate x^^(-oo)?
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