Modular arithmetic
#4
(04/03/2010, 12:18 AM)Stereotomy Wrote: \( 7^{7^{7}} \text{mod} 5 = 3 \)
Is true as well. In fact, thinking about it, the numbers I tried out with this all had b>a. Perhaps that's an additional condition that either b > a or m, n > 1?

There is an article which proves that \( {^n a} \) (which is \( a{\uparrow}^2 n \) in Knuth's arrow notation) finally will be constant for \( n\to\infty \) mod any \( M \), see this thread.


Messages In This Thread
Modular arithmetic - by Stereotomy - 04/02/2010, 07:16 PM
RE: Modular arithmetic - by bo198214 - 04/02/2010, 10:57 PM
RE: Modular arithmetic - by Stereotomy - 04/03/2010, 12:18 AM
RE: Modular arithmetic - by bo198214 - 04/03/2010, 12:00 PM

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