[Regular tetration] [Iteration series] norming fixpoint-dependencies Gottfried Ultimate Fellow Posts: 898 Threads: 130 Joined: Aug 2007 08/31/2010, 05:36 AM (This post was last modified: 08/31/2010, 05:40 AM by Gottfried.) (08/30/2010, 11:14 PM)tommy1729 Wrote: i.e. z<> z^z => z^z =/= (z + z^^2)/2. I explained in an earlier post my misuse of the z^^h-notation. (Oh, that was in the other thread only?, Then - sorry) Ok. To make ascii-writing short I use it there (and now here) in that meaning: using a base b, z^^h is b^b^...^b^z where h is the number of b, in case of continuous: z^^h = $\exp_b^{oh}(z)$ I think that "misuse" can be justified since we usually talk about a fixed chosen base ("b") and discuss the change of parameter z as iteration start, h as iteration "height" and z^^h as iteration result. Reading some "z^z" above I think there is a misunderstanding there. Gottfried Gottfried Helms, Kassel tommy1729 Ultimate Fellow Posts: 1,859 Threads: 402 Joined: Feb 2009 08/31/2010, 11:55 PM (This post was last modified: 09/01/2010, 02:57 PM by tommy1729.) i will explain later ... ( edit ) i started a new thread in the general section related to (mainly) this and my ' f(x) = f(x^2) blunder thread ' « Next Oldest | Next Newest »

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