Quote:ln(sqrt2) gives : ln sgrt2 +- 2 pi k =1/2ln2 +- 2 pi I kNot to nitpick, but rather than saying k is not 0, you should really specify that k is odd (and inequality with 0 is then already implied). I tend to write it as, e.g.,
ln(-sqrt 2) gives: ln sqrt 2+-pi k= 1/2ln 2 +- pi I k but k is not 0 as negative logarithms can only be complex, never real.
~ Jay Daniel Fox