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 how many superfunctions? [was superfunctions of eta converge towards each other] tommy1729 Ultimate Fellow Posts: 1,358 Threads: 330 Joined: Feb 2009 05/26/2011, 10:09 PM (This post was last modified: 05/26/2011, 10:21 PM by tommy1729.) another question is : how many superfunctions can a function have ? in this thread we have a lower and upper superfunction. but when considering complex numbers and non-real fixpoints and general analytic functions , i wonder about how many superfunctions one can have and how to determine them. note that a different branch is not considered another superfunction ! also "the inverse superfunction" is quite a weird concept , since we do not know which superfunction to invert. thinking about this seems complicated at first , but maybe i missed something trivial. i think this question has not been asked here before and is not easy to find in books. correct me if im wrong. regards tommy1729 edit : hmm , on the other hand , following the conjecture of this thread it seems the lower and upper are in fact " the same " in some sense. so , only 1 " true superfunction " for all entire functions afterall ? if so then the OP must be correct in the sense that the behaviour of 1 function is also seen in the other and visa versa. then only the behaviour of 1 function needs to be shown ... in this case (thread) might have already happened. bo198214 Administrator Posts: 1,386 Threads: 90 Joined: Aug 2007 05/27/2011, 09:33 AM (This post was last modified: 05/27/2011, 09:35 AM by bo198214.) (05/26/2011, 10:09 PM)tommy1729 Wrote: another question is : how many superfunctions can a function have ? There are different answers. If you just ask about the number of superfunctions, then there are infinitely many. We discussed that already, when ever you have a superfunction F, F(x+1)=f(F(x)) then also the function $G(x)=G(x+\theta(x))$ is a superfunction, for $\theta$ 1-periodic, this should not be new for you. If you however ask, how many *regular* super-functions you have at a given fixpoint, i.e. superfunction from regular fractional iterations, i.e. which have an asymptotic powerseries development at the fixpoint, which is equal to the formal fractional iteration powerseries, then there is a clear answer: You look at the powerseries development of the corresponding function, for simplicity we assume fixpoint at 0. $f(x)=f_1 x + f_2 x^2 + \dots$, assume $f_1\neq 0$ Hyperbolic: $|f_1|\ne 1$: there is exactly one regular superfunction Parabolic: $f(x)=x + f_m x^m + f_{m+1}x^{m+1} + \dots$: There are exactly 2(m-1) regular superfunctions. For example $e^x-1=x+x^2/2+\dots$, that's why we have 2*(2-1)=2 regular superfunctions. One from left and one from right. Generally there are $2(m-1)$ petals around the fixpoint, which are alternatingly attractive and repellant (in our example coming from left is attractive and coming from right repellant), on each petal there is defined a different regular Abel function (which is the inverse of a superfunction). The whole thing is called the Leau-Fatou-flower and is kinda standard in holomorphic dynamics (see for example the book of Milnor mentioned on the forum). tommy1729 Ultimate Fellow Posts: 1,358 Threads: 330 Joined: Feb 2009 05/27/2011, 10:48 PM fascinating. nice answer , but like most nice answers in math , it felt too short. your answer is very enlightening , but at the same time it brings lots of questions. holomorphic dynamics is not my thing , but i would love to learn more about it. however it is hard to ask a formal , clear , direct and good question. one thing that puzzles me is how the riemann surfaces of the many superfunctions relate to each other ... also of intrest and similar to the other thread , if there are 2m regular superfunctions f_i from one fixpoint , is it true that at least m of those can be chosen such that f_i(z) = f_j(z + p_q(z) + Q) ?? where p_q(z) is a periodic function and Q is a constant. another question if a function F(z) ( not moebius ) has only 2 fixpoints , fixpoint fp1 has N regular superfunctions and fixpoint fp2 has M regular superfunctions , then how many regular superfunctions does F(z) has at most or at minimum ? its kinda hard to visualize all this ... bo198214 Administrator Posts: 1,386 Threads: 90 Joined: Aug 2007 05/28/2011, 09:18 AM (05/27/2011, 10:48 PM)tommy1729 Wrote: if there are 2m regular superfunctions f_i from one fixpoint , is it true that at least m of those can be chosen such that f_i(z) = f_j(z + p_q(z) + Q) ?? where p_q(z) is a periodic function and Q is a constant. Yes, first a (regular) superfunction is always undetermined by an x-axis shift, this is the role of Q. Second if you have any two superfunctions f and g, then $g^{-1}(f(x))$ (if g is suitably injective) is always a 1-periodic function, which follows from the definition of Abel and superfunction. tommy1729 Ultimate Fellow Posts: 1,358 Threads: 330 Joined: Feb 2009 05/28/2011, 12:12 PM my other questions are harder i assume. bo198214 Administrator Posts: 1,386 Threads: 90 Joined: Aug 2007 05/28/2011, 12:25 PM (This post was last modified: 05/28/2011, 12:26 PM by bo198214.) (05/28/2011, 12:12 PM)tommy1729 Wrote: my other questions are harder i assume. Well I mean in most cases the regular iteration at one fixpoint is different from the one at the other. In the case of real analytic function with two real fixpoints they are equal only in the case of fractional linear (i.e. moebius) function. This is due to a result of Karlin&McGregor, I am not aware of other "global" results about regular iteration at different fixpoints. tommy1729 Ultimate Fellow Posts: 1,358 Threads: 330 Joined: Feb 2009 05/29/2011, 05:27 PM could you plz provide a reference for that karlin&McGregor result ? bo198214 Administrator Posts: 1,386 Threads: 90 Joined: Aug 2007 05/29/2011, 09:20 PM (This post was last modified: 05/29/2011, 09:22 PM by bo198214.) (05/29/2011, 05:27 PM)tommy1729 Wrote: could you plz provide a reference for that karlin&McGregor result ? Its already contained in this post. If you also want to read some French continuing the topic, perhaps you can read: "Etude theorique et numerique de la fonction de Karlin-McGregor", Serge Dubuc, Journal d'Analyse Math.. Vol. 42 (1982 / 83) sheldonison Long Time Fellow Posts: 631 Threads: 22 Joined: Oct 2008 05/31/2011, 07:38 PM (This post was last modified: 05/31/2011, 07:57 PM by sheldonison.) (05/28/2011, 09:18 AM)bo198214 Wrote: .... Second if you have any two superfunctions f and g, then $g^{-1}(f(x))$ (if g is suitably injective) is always a 1-periodic function, which follows from the definition of Abel and superfunction.This 1-periodic function interests me. $\theta(z)=g^{-1}(f(z))-z$, where g(z) is an entire function, and f(z) is some other super function for the same base. We already discussed base eta=e^(1/e), where g is the upper superfunction (cheta), and f is the regular $\text{sexp}_\eta(z)$ function. Theta is a 1-cyclic function defined for imag(z)>=0 as long as z isn't an integer. This is similar to the case for bases>eta, where f=sexp(z), which is tetration, and is defined from g(z), the regular superfunction, by a theta(z). Here theta(z) is the Kneser Riemann mapping function, with singularities at the integers. Theta(z) quickly decays to zero as imag(z) increases. So, theta(z) is defined if imag(z)>=0 and z is not an integer. The Schwarz reflection property is used to define sexp(z) for imag(z)<0. For bases

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