10/01/2007, 08:18 AM
Hi, Gottfried! Thank you for this interesting link!
As a matter of fact, the number of hexagrams of the Yi-King is 2^6 = 64 = 2^(3*2). Unfortunately, this is not a remarkable 2 # n number. In fact, we have:
2#0 = 1, 2#1 = 2, 2#2 = 4 (like 2+2 = 2*2 = 2^2, and ... so on), 2#3 = 16, 2#4 = 65536, and ... so on. But there is a link with the ... emperor of China. Number 65536 is also equal to 256 x 256, the cartesian product of two eight-bit codes, usable (and in fact presently used) by China for the binary coding of the Chinese ideographic alphabet. Two-tetra-4 is sufficient. The world is small and beautiful.
Thank you again.
Gianfranco
As a matter of fact, the number of hexagrams of the Yi-King is 2^6 = 64 = 2^(3*2). Unfortunately, this is not a remarkable 2 # n number. In fact, we have:
2#0 = 1, 2#1 = 2, 2#2 = 4 (like 2+2 = 2*2 = 2^2, and ... so on), 2#3 = 16, 2#4 = 65536, and ... so on. But there is a link with the ... emperor of China. Number 65536 is also equal to 256 x 256, the cartesian product of two eight-bit codes, usable (and in fact presently used) by China for the binary coding of the Chinese ideographic alphabet. Two-tetra-4 is sufficient. The world is small and beautiful.
Thank you again.
Gianfranco