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Searching for an asymptotic to exp[0.5]
#38
Related to mike's conjecture and some of my own about derivatives ,Im intrested in a fake alternating solution.

I use the following strategy :

S(x) = exp^[0.5](x)
For all x > 1 :

- a_n x^n + (a_n + b_n) x^(n+1) < S(x)

n ln(x) + ln( -a_n + (a_n + b_n) x ) < S(ln(x))

(x=exp(X) and b_n/a_n = c_n )

n X + ln(a_n) + ln( - 1 + (1 + c_n) exp(X) ) < S(X)

We could try the same with sexp too.

regards

tommy1729
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Messages In This Thread
RE: Searching for an asymptotic to exp[0.5] - by tommy1729 - 06/30/2014, 01:27 AM

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