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Searching for an asymptotic to exp[0.5]
#49
A competitor for the 2sinh method is ofcourse

ln(ln(f(exp^[2](z)))).

If we take more ln and exp iteration we also end up with a c^oo function.
But it seems to converge faster.

regards

tommy1729
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RE: Searching for an asymptotic to exp[0.5] - by tommy1729 - 07/14/2014, 12:27 AM

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