Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
Rational sums of inverse powers of fixed points of e
jaydfox Wrote:The first one looks about right, meaning it looks familiar at a glance.

Ahh, just I got it myself. I got for the first few approximations (upscaled by factorials)
so I have it now. But for the first n=96 entries I needed ~120 secs, using also only 96 fixpoints (Eulersumming them).
Gottfried Helms, Kassel
Yes, they converge very rapidly. The fixed points increase by approximately 2*pi*I as we move away from the real line, so they form an arithmetic sequence to a first approximation. Therefore, they'll converge about as fast as the partial sums of the zeta function. So yes, we shouldn't need very many fixed points to calculate the coefficients of the rational numbers, though I haven't bothered to figure out if some minimum number of fixed points would suffice for all sums.

My main interest in calculating 100,000 fixed points was to generate continued fractions for each sum, and try to use those to provide strong numerical evidence that the infinite sums indeed converge on rational numbers.
~ Jay Daniel Fox
jaydfox Wrote:Anyway, in the meantime, I wanted to try to figure out how to calculate the numerators. It seems to me that they deserve their own Sloane sequence, considering how surprising it was (to me) to get rational sums.

Hmm, this may not be of much help, at least I didn't find out a useful simplification. Anyway.

If I use my formula for complex fixpoint for real base s, with the single independent parameter beta:

u = alpha + beta*i

t = exp(u) = a + b*i
s = exp(u/t)

and in your example s=e, then these formulae can possibly be reversed to determine the allowed values for beta.

The only thing I know already is, that the different allowed beta_k are roughly periodic at k*2*pi+eps_k with eps_k decreasing towards zero.

So for any t of all t_k, omitting the index,
t = exp( alpha + beta*i)
= exp(alpha)*cos(beta) + exp(alpha)*sin(beta)*I
1/t = exp(-alpha - beta*i) = exp(-alpha)/(cos(beta)+sin(beta)*i)
= exp(-alpha)*(cos(beta)-sin(beta)*i)

Now you consider the sum of 1/t and 1/conj(t) as one term v:
v=1/t + conj(1/t) = 2*exp(-alpha)*cos(beta)
v=2 * exp(-beta/sin(beta)*cos(beta))*cos(beta)
and ask, whether the sum of all v_k add up to a rational...

I don't know, how to proceed from here; the most difficult thing is surely the reverse determination of the possible beta's from the given base-parameter s=e.

Hmmm ... an apple without vitamins...

Gottfried Helms, Kassel
Hmm, I didn't follow your post, but it's early and I've been thinking about the singularity at 0 that I only just noticed. Actually, I haven't quite been following the maths in the Imaginary zeros of f(z)= z^(1/z) discussion. (Not because you didn't explain the maths well, but because I haven't devoted the time yet.)

As for the numerators, I already found a Sloane series (A009306), which by changing every other sign and removing the first couple terms gives me the series I found. A separate Sloane series probably isn't required, merely the simple rules for how to get the numerators from the existing series.

The calculation of the terms in the Sloane series is done with basic functional composition of power series with rational coefficients, so determining an arbitrary term should be straightforward, and from the matrices involved in the composition we could derive a (not necessarily simple) formula.
~ Jay Daniel Fox
This is indeed an interesting connection.
Now my quick 2 cents about it.

First, we want the explicit function of which the sums of the powers of the inverted fixed points are the coefficients. We compare Jay's beginnin with index 1 in the first row with Sloane's beginning at index 1 in the second row:

Obviously we have to move the lower row to the left which is the same as dividing Sloane's function by . We get then

and see that the sign is swapped for each uneven power, which can be achieved by using instead of .
So we get
with .

for . If we transform this further via we get
to prove.

Looks strange, perhaps I made an error somewhere.

Possibly Related Threads...
Thread Author Replies Views Last Post
  tetration from alternative fixed point sheldonison 22 45,830 12/24/2019, 06:26 AM
Last Post: Daniel
  Thoughts on hyper-operations of rational but non-integer orders? VSO 2 2,727 09/09/2019, 10:38 PM
Last Post: tommy1729
  Inverse Iteration Xorter 3 5,421 02/05/2019, 09:58 AM
Last Post: MrFrety
  Inverse super-composition Xorter 11 21,035 05/26/2018, 12:00 AM
Last Post: Xorter
  Are tetrations fixed points analytic? JmsNxn 2 5,258 12/14/2016, 08:50 PM
Last Post: JmsNxn
  the inverse ackerman functions JmsNxn 3 8,409 09/18/2016, 11:02 AM
Last Post: Xorter
  Rational operators (a {t} b); a,b > e solved JmsNxn 30 58,808 09/02/2016, 02:11 AM
Last Post: tommy1729
  Removing the branch points in the base: a uniqueness condition? fivexthethird 0 2,559 03/19/2016, 10:44 AM
Last Post: fivexthethird
  Inverse power tower functions tommy1729 0 2,846 01/04/2016, 12:03 PM
Last Post: tommy1729
  Derivative of exp^[1/2] at the fixed point? sheldonison 10 17,083 01/01/2016, 03:58 PM
Last Post: sheldonison

Users browsing this thread: 1 Guest(s)