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 Mizugadro, pentation, Book tommy1729 Ultimate Fellow Posts: 1,491 Threads: 355 Joined: Feb 2009 01/15/2015, 01:12 PM (This post was last modified: 01/15/2015, 01:20 PM by tommy1729.) Why isnt pentation defined as $pent(z) = sexp^{[z]}(x_0) =$ lim $sexp^{[n]}( L' ^z slog^{[n]}(x_0))$ Do you really believe lim $sexp^{[n]}(f(L,L',z)) =$ lim $sexp^{[n]}( L' ^z slog^{[n]}(x_0))$ where $f$ is a simple elementary function ? Afterall approximating slog^[n] with an elementary function seems wrong/divergent ? Lim $sexp^{[n]}(x+y)$ is usually very different from lim $sexp^{[n]}(x)$ even if $y$ is small or getting smaller with growing $n$. Also its not defined as lim $sexp^{[n]}(L' ^{z-n})$. I assume its (your def of pentation in the paper) meant as an acceleration of lim $sexp^{[n]}(L' ^{z-n})$. If not that would appeal weird and dubious to me. Is that acceleration really a big improvement ? Still reading and thinking , I dont have much time ... regards tommy1729 « Next Oldest | Next Newest »